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首先你要弄清楚方位角是对线段说的
资料介绍
首先你要弄清楚方位角是对线段说的，没有“测站点坐标方位角”这说法。 2.线段的方位角的正切值＝y坐标差÷x坐标差。而后比较线段终点和起点的x、y坐标的大小，判断其在哪个像限，得到正确角度。 3.现在你遇到的问题中，方位角已知，后视点坐标已知，条件还不够，没法算。
部分文件列表
| 文件名 | 文件大小 | 修改时间 |
| Gauss-Kruger Projection/Backup/Gauss-Kruger Projection/Ellipsoid.cs | 2KB | 2011-11-05 11:54:10 |
| Gauss-Kruger Projection/Backup/Gauss-Kruger Projection/Form1.cs | 9KB | 2011-11-05 12:54:50 |
| Gauss-Kruger Projection/Backup/Gauss-Kruger Projection/Form1.Designer.cs | 23KB | 2011-11-05 12:54:50 |
| Gauss-Kruger Projection/Backup/Gauss-Kruger Projection/Form1.resx | 7KB | 2011-11-05 12:54:50 |
| Gauss-Kruger Projection/Backup/Gauss-Kruger Projection/Gauss-Kruger Projection.csproj | 4KB | 2011-11-05 11:54:10 |
| Gauss-Kruger Projection/Backup/Gauss-Kruger Projection/Method.cs | 9KB | 2011-11-05 13:03:32 |
| Gauss-Kruger Projection/Backup/Gauss-Kruger Projection/Program.cs | 1KB | 2011-11-01 22:18:12 |
| Gauss-Kruger Projection/Backup/Gauss-Kruger Projection/Properties/AssemblyInfo.cs | 1KB | 2011-11-01 22:15:28 |
| Gauss-Kruger Projection/Backup/Gauss-Kruger Projection/Properties/Resources.Designer.cs | 3KB | 2011-11-01 22:15:28 |
| Gauss-Kruger Projection/Backup/Gauss-Kruger Projection/Properties/Resources.resx | 5KB | 2011-11-01 22:15:28 |
| Gauss-Kruger Projection/Backup/Gauss-Kruger Projection/Properties/Settings.Designer.cs | 1KB | 2011-11-01 22:15:28 |
| ... | ||
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